To solve for Thevenin Voltage for the first problem we must place a current source where the Thevenin Voltage is to be found, like the figure below at the far right.
When we simulate the DC Sweep a graph is given to analyze.
When my current source is at zero (x-axis) my voltage is 112.50 volts. This is my Thevenin Voltage. For the slope of this graph I get (695.833V-112.500V)/.1A, which is equal to 5833.33 V/A, this is my Thevenin Resistance.
To find my Thevenin Equivalents in my next problem I will perform the same procedures like before.
After Running DC Sweep I get my Thevenin Voltage to be 75.65 Volts. The slope of this graph is (105.065 V - 75.645 V)/.4 A= 73.55 ohms.
The second part of this problem asks to find the value of the resistor load that will dissipate as much power as possible and to find that max power. The first thing to do is to transform the above circuit into the Thevenin Equivalent circuit. Then we set up the DC Sweep to give us the graph that we want
When the Circuit is simulated, the graph is traced to find the max power and the value of the resistor load. The graph below shows that in order to dissipate maximum power the resistor has to have the value of 73.55 ohms. At that point the graph states that the value of max power will be 19.453 Watts.
No comments:
Post a Comment